Question

two years ago, the age of the father was three and half times the age of his daughter then. six years hence the age of father will be ten years more than twice the age of his daughter then find their present ages.

Answer 1

Answer:

Age of father = 44 years , Age of daughter = 14 years

Step-by-step explanation:

let age of father be x , daughter be y

x - 2 = 7/2( y-2 )

⇒x - 2 = 7y/2 - 7

⇒2x -4 = 7y -14

⇒7y - 2x = 10 -----> (1)

x+6 = 2(y+6) +10

⇒x+6 = 2y+22

⇒x-2y = 16 -----> (2)

Multiply (2) by 2

7y - 2x = 10

-4y + 2x = 32

⇒3y = 42

⇒ y = 14

⇒ x = 2(14) + 16 = 44