Question

Two years ago the father age was the square of his son's age.Two years later, his age will be four times the age of his son. Find their present age.

Answer 1

Answer:

let son's age 2 years ago be x

father's age 2 years ago will be x²

son's present age will be x + 2

father's present age will be x² + 2

son's age after 2 years will be x + 2 + 2 = x + 4

father's age after 2 years will be x²+2+2 = x²+4

as per the given condition x²+4 = 4(x+4)

x² + 4 = 4x + 16

x²- 4x - 12 = 0

x² - 6x + 2x - 12 = 0

x ( x - 6) + 2 ( x - 6 ) = 0

(x + 2) (x - 6) = 0

x+ 2 = 0 x = - 2 × age can not be negative

x- 6 = 0 x = 6 √

therefore son's present age is 6 + 2 years

=> 8 years

father's present age = 6²+2

=> 36 + 2

=> 38 years