Question

Two years ago, the father was five times as old as his son 2 years later. His age will be 8 more than three times the age of son find the present ages of father and son​

Answer 1

Answer:

The age of father is 42 yrs and the age of sun is 10 yrs.

Step-by-step explanation:

Let the age of father is x years and that of son is y years.

Then by the given question,

x-2=5(y-2)

or, x-5y=-10+2

or, x-5y=-8

or, x=5y-8

x+2=3(y+2)+8

or, x-3y=6+8-2

or, 5y-8-3y=12

or, 2y=12+8

or, y=20/2

or, y=10

then x=5y-8=50-8=42

Then, the age of father is 42 yrs and the age of sun is 10 yrs.

PLS MARK AS BRAINLIEST

HOPE IT HELPS...

Answer 2

Let present age of father be x and present age of son be y.

2 yrs ago:

x-2 = 5(y-2)                  ... (1)

2 yrs hence:

x+ 2= 8 + 3(y+2)           ... (2)

From (1), x = 5y - 8

Substitute the value of x in (2),

5y-8 +2 = 8+3y +6

2y = 20

y=10

So, x = 50 - 8 = 42

Present age of father = 42 yrs

Present age of son= 10 yrs

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Hope it helps.....Brainliest Pls