Question

Two years ago the man's age was three times the square of his son's age. Three years hence his age will be four times his son's age. Find their present ag

Answer 1

Step-by-step explanation:

man age be x

son age be y

from 1st condition

x-2=3(y-2)^2

x-2 = (3y-6)^2

x-2=9y^2-36y+36

x-2=9y^2-18y-18y+36

x-2=9y(y-2)-18(y-2)

x-2=(y-2)(9y-18)

x-2= y=2 or y =18/9

x-y=4........(1)

from 2nd condition

x+3 =4(y+3)

x+3=4y+12

x-4y=12-3

x-4y =9.........(2)

subtracting equation 1and 2

x-4y=9

-

x-y=4

_____

-3y=5

y=-3/5

put in equation 1

x-y=4

x+3/5 =4

x=4-3/5

=20-3/5

17/5