Math, asked by chandanmahtokumar11, 5 hours ago

Two years ago, the population of a town was 25,000.If the annual decrease during two successive years at the rate of 5% and 4%. What is its present population?​

Answers

Answered by iamgojoof6eyes
1

Answer:

22800

Step-by-step explanation:

Given:

Total population of the town = 25000

decrease of the population in the first year = 5%

decrease of the population in the second year = 4%

The present population of the city =?

Now,

Decrease of the population in first year (in numbers) = 5% of 25000 = 5/100 × 25000 = 125000/100 = 1250

Now population of the city present in second year = 25000 - 1250 = 23750

Decrease of the population in second year (in numbers) = 4% of the population present in second year = 4% of 23750 = 4/100 × 23750 = 950

Population presents in third year (present population) = 23750 - 950 = 22800

Similar questions