Math, asked by sharadsoni7, 1 year ago

two years ago the population of a twon was 80000 if the annual increase during two successive year be at the rate of 5% and 4% respectively what is its present population

Answers

Answered by shinku34
0
87200 is answer buddy
Answered by chakrabortytanoy98
0

Answer:


Step-by-step explanation:

Two years ago the population of a town was like 80000

Now the annual increament for the next year be like 5%

So that year after the increament the population be like =5/100*80000+80000=84000

So the population is 84000

Again for the next year the increment was 4%

So the current population is 4/100*84000+84000=3360+84000=87360.

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