two years ago the ratio of the ages of a mother and her daughter was 8:1. after 2 years the ratio of their ages will be 4 :21 today how many years is the mother than her daughter
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Step-by-step explanation:
Let the ages of mother and her daughter be 8x,X before 2 years
Present ages are 4x,21x
According to the problem,
8x+X+4=21x+4x-4
9x+4=25x-4
4+4=25x-9x
8=16x
X=2 years
age of daughter=4(2)=8 years
age of mother =21(2)=42 years
Difference between their ages =42-8
=34 years
Therefore mother is 34 years more than her daughter.
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