Two years ago the ratio of the ages of Manoj and Shyam
was 15:11. Two years hence the ratio of their ages will
be 17:13. What is the present age of Shyam?
Answers
Let the present age of Manoj and Shyam be x years and y years respectively.
Then, two year ago,
x−2/y−2 = 15/11
or, 11x - 22 = 15y - 30
or, 11x - 15y = -8 ... (i)
Again, after two years,
x+2/y+2= 17/13
or, 13x + 26 = 17y + 34
or, 13x - 17y = 8 ... (ii)
Multiplying eqn (i) by 13 and eqn (ii) by 11,
we get
143x - 195y = - 104
- 143 + 187y = - 88
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y = 24 years
• Let present age of Manoj be M and present age of Shyam be N
2 years ago
• Age of Manoj = (M - 2) years
• Age of Shyam = (N - 2) years.
» Two years ago the ratio of the ages of Manoj and Shyam was 15:11.
A.T.Q.
=>
Cross-multiply them
=> 11(M - 2) = 15(N - 2)
=> 11M - 22 = 15N - 30
=> 11M - 15N = - 30 + 22
=> 11M - 15N = - 8 ______ (eq 1)
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» Two years hence the ratio of their ages will be 17:13.
A.T.Q.
=>
Cross-multiply them
=> 13(M + 2) = 17(N + 2)
=> 13M + 26 = 17N + 34
=> 13M - 17N = 34 - 26
=> 13M - 17N = 8 ______ (eq 2)
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On multiplying (eq 1) with 13 and (eq 2) with 11 we get;
=> 143M - 195N = - 104 _______ (eq 3)
=> 143M - 187N = 88 _______ (eq 4)
• Subtract (eq 4) from (eq 3)
=> 143M - 195N - (143M - 187N) = - 104 - 88
=> - 195N + 187N = - 192
=> -8N = - 192
=> N = 192/8
=> N = 24
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Present age of Shyam = 24 years (N)
__________ [ ANSWER ]
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