two years ago the value of machine was rupees 62500 if its value depreciates by 4% every year what is its present value
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Answered by
40
Answer:
57600
Step-by-step explanation:
P = 62500, Time(n) = 2 years, R = 4%.
A = P(1 + r/100)^n
= 62500(1 - 4/100)^2
= 62500(24/25)^2
= 36000000/625
= 57600
Therefore, present value is 57600.
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Answered by
24
Answer:
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