Two years compound interest at rate of 10% per annum for an amount is Rs 420/- What will be the
simple interest for 3 years for the same amount at the same rate.
?
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Raghunath answered 3 year(s) ago
Find the compound interest on Rs 4000 for 2.5 years at 10% per annum.
Class-VIII Maths
person
Asked by Manish
Feb 18
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Raghunath , SubjectMatterExpert
Member since Apr 11 2014
Principal(P) = Rs 4000
Rate of Interest(r ) = 10%
Time = 2.5 years
Here first we take n = 2 years.
A = P( 1 + r /100)n Where A = Amount and n = number of years
A = 4000 (11/10)2
A = 4000 ( 121 / 100 )
A = Rs 4840
The Amount after two years = Rs 4840
Now Principal = Rs 4840
Simple interest for last ½ year is = PRT/100 = (4840 × 10 × 1 / 2) / 100 = Rs.242
Amount after 2 ½ year = Rs 4840 + Rs 242 = Rs 5082
C.I = A - P
C.I = Rs 5082 - Rs 4000 = Rs1082
∴ The compound interest is Rs 1082.
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Raghunath answered 3 year(s) ago
Find the compound interest on Rs 4000 for 2.5 years at 10% per annum.
Class-VIII Maths
person
Asked by Manish
Feb 18
5 Likes
14444 views
editAnswer
Like Follow
1 Answers
Top Recommend
| Recent
person
Raghunath , SubjectMatterExpert
Member since Apr 11 2014
Principal(P) = Rs 4000
Rate of Interest(r ) = 10%
Time = 2.5 years
Here first we take n = 2 years.
A = P( 1 + r /100)n Where A = Amount and n = number of years
A = 4000 (11/10)2
A = 4000 ( 121 / 100 )
A = Rs 4840
The Amount after two years = Rs 4840
Now Principal = Rs 4840
Simple interest for last ½ year is = PRT/100 = (4840 × 10 × 1 / 2) / 100 = Rs.242
Amount after 2 ½ year = Rs 4840 + Rs 242 = Rs 5082
C.I = A - P
C.I = Rs 5082 - Rs 4000 = Rs1082
∴ The compound interest is Rs 1082.
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600 will be the answer
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Bhupender999:
where you got 21% ?
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