Two years hence a boy will be two times as old as a girl. Before four years, he was three times as old as the girl was. Find their present age.
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Answer:
The present age of
(i) girl = 10 years
(ii) boy = 22 years
Step-by-step explanation:
Let the present age of girl be x and the present age of boy be y. Then
According to the question,
Equation (i) 2 + y = 2(x + 2)
=> 2 + y = 2x + 4 => 2x - y = -2
Equation (ii) y - 4 = 3(x - 4)
=> y - 4 = 3x - 12 => 3x - y = 8
Subtracting the equation(i) from equation(ii) , we get
x = 10
Therefore, y= 2x + 2 = 3x - 8 = 22
Then the present age of
(i) girl = 10 years
(ii) boy = 22 years
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