Question

Two years hence a father will be six times as old as his son. Three years ago the father was five times as old as his son will be two years hence find the present ages of father and son.​

Answer 1

Answer:

SON'S PRESENT AGE : 14 years.

FATHER'S PTESENT AGE: 38 years.

Step-by-step explanation:

Let son's age = x

Two years ago son's age= x-2.

His Father's age at that time = 3(x-2).

Present age of Father = 3x-6+2=3x-4

Two years hence father's age=3x-4+2=3x-2.

Two years hence son's age = x+2.

Given :-5*(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S PTESENT AGE: 38 years.

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Answer 2

sons age 14

fathers age 38