Question

two years later a father will be 8 years more than three times the age of his son also make graph​

Answer 1

Step-by-step explanation:

Suppose, present age of father = x years and present age of son = y years

Two years later,

Age of father = (x + 2) years

Age of son = (y + 2) years

Two years later, age of father = 3 × Age of son + 8 years

Given:

$= (x + 2) = 3(y + 2) + 8 \\ = x + 2 = 3y + 6 + 8 \\ = x = 3y + 12$

When age of son, y = 10 years, age of father, x = 3 × 10 + 12 = 30 + 12 = 42 years