two years later a father will be 8 years more than three times the age of the son. taking. the present ages of father and son as x and y respectively weite a linear equation for the above and draw the graph
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two years later father's age will be 8 years more than three times the age of his son. by taking the present ages of father and son as x and y respectively write a linear equation for the above and draw the graph.
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Required Answer:-
To find:- to form a linear equation and to draw graph.
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Solution:-
Let father's present age be x.
and present age of his son be y.
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According to the given condition,
two years later,
Father's age will be (x + 2)
and son's age will be (y + 2)
(x + 2) = 3(y + 2) + 8
x + 2 = 3y + 6 + 8
x + 2 = 3y + 14
x - 3y = 14 - 2
x - 3y = 12 -(i)
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Hope it help you :)
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