Two years later , a father will be 8 yr more than three times the age of s son. Taking the present ages of father and son ad X and Y respectively, write a linear equation for the above and draw its graph. From the graph, find the age of the father, when the son,s age is 10 yr.
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Answered by
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Heya
Let the father's age be x
Son's age be y
According to the question
x+2 = 8+3(y+2)
x= 3y+6+8-2
x= 3y+12
x-3y-12=0
When the son's age is 10yrs i.e y=10
x=3(10)+12 = 30+12 = 42 years
Sorry, I couldn't provide you the graph for it.
Hope it helps^_^
Let the father's age be x
Son's age be y
According to the question
x+2 = 8+3(y+2)
x= 3y+6+8-2
x= 3y+12
x-3y-12=0
When the son's age is 10yrs i.e y=10
x=3(10)+12 = 30+12 = 42 years
Sorry, I couldn't provide you the graph for it.
Hope it helps^_^
Answered by
0
Answer:
Heya
Let the father's age be x
Son's age be y
According to the question
x+2 = 8+3(y+2)
x= 3y+6+8-2
x= 3y+12
x-3y-12=0
When the son's age is 10yrs i.e y=10
x=3(10)+12 = 30+12 = 42 years
I hope it's help you.
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