Question

two years later father will be 8 years more than 3 times the age of son. Write a linear equation in two variables by taking the present age of father and son as x and y respectively ​

Answer 1

Answer:

father-x

son -y

so x+2=8+3(y+2)

therefore x-3y=12

Answer 2

Answer:

x+2 = 14 + 3y

Step-by-step explanation:

father's present age = x

so father's age 2 yrs later= 2+x

son's present age = y

so age 2 yrs later = 2+y

so the linear equation is x+2 = 8 + 3(2+y)

                                      or x+2 = 8 + 6 + 3y

                                       = x+2 = 14 + 3y