Question

Two zero of the polynomial p(x) = 4x^2 -12x + 9.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

P(x)=4x

2

+24x+36

Here, a=4,b=24,c=36

p(x)=4x

2

+12x+12x+36

=4x(x+3)+12(x+3)

=(x+3)(4x+12)

=4(x+3)

2

So, the zeros of quadratic polynomial is −3 and −3.

Let α=−3 and β=−3

Sum of zeros = α+β=−3−3=−6

Sum of zeros =−

coefficient ofx

2

coefficient ofx

−

a

b

=

4

−24

=−6

So, sum of zeros =α+β=−

coefficient ofx

2

coefficient ofx

Product of zeros =αβ=(−3)(−3)=9

Also, product of zeros =

coefficient ofx

2

constant term

=

a

c

=

4

36

=9

So, product of zeros =αβ=

cofficient ofx

2

constant term