Question

two zeroes 2,-2 find third zero by dividion algorithm 3x³+4x²+5x-13​

Answer 1

Answer:3x³+4x²  +5x-13   by 2 , -2

Step-by-step explanation :

let g(x) = y

now

divisor * quotient + remainder  = dividend

y * (3x+10) + 16x-43 = 3x^3 + 4x² + 5x - 13

y * (3x+10) = 3x^3 + 4x² - 11x + 30

now we can calculate the value of y by dividing

3x^3 + 4x² - 11x +30 from  3x+10

so 

y = x² - 2x + 3