two zeroes are √3/√2 and other zero is -√3/√2.find the polynomial
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p(x)=x^2-(sum of zeroes)X+product of zeroes
=x^2-[√3/√2+(-√3/√2)+√3/√2×-√3/√2=0
=x^2-(0)-3/2=0
=x^2-3/2=0 or
=2x^2-3=0
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