Question

two zeros of P(X) is equal to x^3 6x^2+ 11 x - 6 are 2 and 3. find the third zero​

Answer 1

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Correct Question:-

• Two zeros of P(X) is equal to x^3 6x^2+ 11 x - 6 are 2 and 3. find the third zero?

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Answer:- 1 is third zero of

this equation

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Step by step explanation:-

$⇢ {x}^{3} - {6x}^{2} + 11x - 6 \\ \\ ⇢ {x}^{3} - {x}^{2} - {5}^{2} + 5x + 6x - 6 \\ \\ ⇢ {x}^{2} (x -1) - 5x(x - 1) + 6(x - 1) \\ \\ ⇢(x - 1) ( {x}^{2} - 5x + 6) \\ \\ ⇢(x - 1)( {x}^{2} - 2x - 3x + 6) \\ \\ ⇢(x - 1)(x(x - 2) - 3(x - 2)) \\ \\ ⇢(x - 1)(x - 2)(x - 3) - - - - - (i)$

Now solve (i) equation for zeros of this equation.

⇢ x-1=0

⇢x=1

⇢x-2=0

⇢x=2

⇢x-3=0

⇢x=3

So , zeros of this equation are 1, 2 and 3.

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How I solve this....

• First factorise the equation.
• Solve the last factors of this equation for finding zeros of any equation.

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