Twobspherical balls each of mass 1 kg are placed 1 cm apart thrbgravitatiinal force
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Let the mass of the light body = m kg , its velocity = v m/s.
Let the mass of the heavy body = M kg, M > m , its velocity V m/s.
KE = (mv)²/ (2m) = (MV)²/(2M )
(mv)²/(MV)² = m/M < 1 => mv < MV
The heavier body has higher momentum.
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2) lighter body: m kg and velocity V m/s
heavier body : 2 m and velocity V/2 m/s
Their momentum is same.
But KE : 1/2 m V² : 1/2 (2m) (V/2)²
KE : 1 : 1/2
The lighter body has a higher KE
I hope you understand it.
Let the mass of the heavy body = M kg, M > m , its velocity V m/s.
KE = (mv)²/ (2m) = (MV)²/(2M )
(mv)²/(MV)² = m/M < 1 => mv < MV
The heavier body has higher momentum.
===================================
2) lighter body: m kg and velocity V m/s
heavier body : 2 m and velocity V/2 m/s
Their momentum is same.
But KE : 1/2 m V² : 1/2 (2m) (V/2)²
KE : 1 : 1/2
The lighter body has a higher KE
I hope you understand it.
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