Question

Twoconcentriccirclesareofradii10cmand8cm,thenthelengthofthechordofthelarger circlewhichtouchesthesmallercircleis:

Answer 1

Answer:

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Answer 2

Answer:

12 cm

Step-by-step explanation:

the radius of smaller circle will be perpendicular on the chord and will bisect the chord. two right triangles will be formed each with 10cm as hypotenuse and 8 cm as one side

the other side i.e. half the chord will be

√10^2 - 8^2

√100-64

√36

= 6

length of chord = 2*6 = 12 cm