Twoconcentriccirclesareofradii10cmand8cm,thenthelengthofthechordofthelarger circlewhichtouchesthesmallercircleis:
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12 cm
Step-by-step explanation:
the radius of smaller circle will be perpendicular on the chord and will bisect the chord. two right triangles will be formed each with 10cm as hypotenuse and 8 cm as one side
the other side i.e. half the chord will be
√10^2 - 8^2
√100-64
√36
= 6
length of chord = 2*6 = 12 cm
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