twp numbers a and b sur selected randomly from the integers 1 to 10 what is the probability that a/b is an integer
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Answered by
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Answer:
Given,two numbers are selected without replacement from integers 1 to 10.
Now, favourable cases for which
b
a
will be an integer are:
1
2
=2;
1
3
=3;
1
4
=4;
2
4
=2;
1
5
=5;
1
6
=6;
2
6
=3;
3
6
=2;
1
7
=7;
1
8
=8;
2
8
=4;
4
8
=2;
1
9
=9;
3
9
=3;
1
10
=10;
2
10
=5;
5
10
=2
∴, favourable number of cases=17
Total cases are:
(
2
1
,
3
1
,...
10
1
),(
1
2
,
3
2
,...,
10
2
),...,(
1
10
,
2
10
,
3
10
,...,
9
10
)
So, total number of cases=9×10=90
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