twuce the square of the sum of a number and 3 is 98. find the number.
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Let x be the missing number.
The equation is:
● 2(x+3)^2 = 98
Divide both sides by 2
●(2/2)×(x+3)^2 = 98/2
● (x+3)^2 = 49
● (x+3) = -√49 or (x+3) = √49
● (x+3) = -7 or (x+3) = 7
● x = -7–3 or x = 7–3
● x = -10 or x = 4
So x has two values.
x = {4, -10}
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