Math, asked by bryanta882, 9 months ago

Tyler simplified the expression x Superscript negative 3 Baseline y Superscript negative 9. His procedure is shown below.x Superscript negative 3 Baseline y Superscript negative 9 = StartFraction 1 Over x cubed EndFraction times StartFraction 1 Over y Superscript negative 9 EndFraction = StartFraction 1 Over x cubed y Superscript negative 9 EndFraction What is Tyler’s error?Both powers should be in the numerator with positive exponents.Both powers should be in the denominator with positive exponents.The power x cubed should be in the numerator and the power y Superscript 9 in the denominator.The power y Superscript 9 should be in the numerator and the power x cubed in the denominator.

Answers

Answered by cherylsea
58

Answer:

Both powers should be in the denominator with positive exponents.

Step-by-step explanation:

I took the edgenuity test

Attachments:
Answered by pruthaasl
2

Correct question:

Tyler simplified the expression x⁻³y⁻⁹. His procedure is shown below:

x^{-3}y^{-9} = \frac{1}{x^3} \frac{1}{y^{-9}} = \frac{1}{x^3y^{-9}}

What is Tyler's error?

1) Both powers should be in the numerator with positive exponents.

2) Both powers should be in the denominator with positive exponents.

3) The power x³ should be in the numerator and the power y⁹ in the denominator.

4) The power y⁹ should be in the numerator and the power x³ in the denominator.

Answer:

Tyler's error was 2) Both powers should be in the denominator with positive exponents.

Step-by-step explanation:

The expression given is x⁻³y⁻⁹.

According to the rules of indices, negative powers in the numerator become positive in the denominator.

Therefore, the expression will be simplified as follows:

x^{-3}y^{-9} = \frac{1}{x^3} \frac{1}{y^9}

x^{-3}y^{-9} = \frac{1}{x^3y^9}

Tyler did not change the sign of the power of y when shifting it from the numerator to the denominator.

Therefore, the correct answer is that both the powers should be in the denominator with positive exponents.

#SPJ3

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