Type A milk cost of price Rs 35 per litre is mixed with type B milk having cost price Rs 50 per litre in the ratio 3:2 respectively. Then find the selling price (per kg) of the final mixture when sold at 25% profit?(in Rs)
Answers
Refer to the attachment
Step-by-step explanation:
Answer:
In what ratio must water be mixed with milk costing 12 per litre to obtain a mixture of 8 per litre?
Let's assume cost of water is 0,
And the amount of water in mixture be x litres, and amount of milk in mixture be y litres,
So as per question the mixture would be sold a 8 Rs/litre
=> Cost of water per litre times amount of water in mixture of 1 litre + Cost of milk per litre times amount of milk in mixture of 1 litre must be equal to required cost of 1 litre mixture times 1 litre(total mixture quantity)
Mathematically,
0*x + 12*y = 8*1
=> 12 y = 8
=> y=2/3 litre
Now since total mixture is 1 litre,
So x = 1-y
x = 1-(2/3) = 1/3 litre
So ratio of water to milk in mixture, to get cost of required mixture to 1 litre = x/y = (1/3)/(2/3)
=> Ratio of water to milk in mixture is 1:2
Hope this helps :-)