Math, asked by uditaaich473, 11 days ago

Type A milk cost of price Rs 35 per litre is mixed with type B milk having cost price Rs 50 per litre in the ratio 3:2 respectively. Then find the selling price (per kg) of the final mixture when sold at 25% profit?(in Rs)​

Answers

Answered by MrAlluring
86

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Answered by LaRouge
10

Answer:

In what ratio must water be mixed with milk costing 12 per litre to obtain a mixture of 8 per litre?

Let's assume cost of water is 0,

And the amount of water in mixture be x litres, and amount of milk in mixture be y litres,

So as per question the mixture would be sold a 8 Rs/litre

=> Cost of water per litre times amount of water in mixture of 1 litre + Cost of milk per litre times amount of milk in mixture of 1 litre must be equal to required cost of 1 litre mixture times 1 litre(total mixture quantity)

Mathematically,

0*x + 12*y = 8*1

=> 12 y = 8

=> y=2/3 litre

Now since total mixture is 1 litre,

So x = 1-y

x = 1-(2/3) = 1/3 litre

So ratio of water to milk in mixture, to get cost of required mixture to 1 litre = x/y = (1/3)/(2/3)

=> Ratio of water to milk in mixture is 1:2

Hope this helps :-)

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