Question

Type "A" tea sells for $19 per pound. How many pounds of tea type A should be mixed with

tea of type B that sells for $4 per pound to obtain a 50 pound mixture that sells for $7 per pound?

a) Formulate the equation.

b) Write the answer, provide units.

Answer 1

Let the type A tea be x pound and type B be y pound

a)

x + y = 50 (eqn. no. 1)

19x + 4y = 7(50)

19x + 4y = 350 (eqn. no. 2)

b)

x + y = 50

x = 50 - y

Putting the value of x in the eqn. no. 2

19x + 4y = 350

19(50 - y) + 4y = 350

950 - 19y + 4y = 350

- 19y + 4y = 350 - 950

- 15y = - 600

y = (-600)/(-15)

y = 40

Putting the value of y in the eqn. no. 1

x + y = 50

x + 40 = 50

x = 50 - 40

x = 10

Hence, 10 pound of Type A tea should be mixed be 40 pound of Type B tea to obtain 50 pound mixture that sells for $7 per pound.