Question

Type I:
Example 1.
Solve yzp + zxq = xy.​

Answer 1

Answer:

point Find the general solution of the linear partial differential equation, yzp + zxq =xy. (a) px2-y2-22)F0 (6) o{x2-y2, y2-22 )=0 oxyZ, yZ-x2 (a) P(x2-Z2, z2-x2 )F0 O O b O d *

Explanation:

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