Question

Type the correct answer in each box.
Tom has 28 milk chocolates, and Emily has 24 dark chocolates. They have to divide these chocolates into small packets that each have the same number of dark chocolates and the same number of milk chocolates. They also want to use all of the chocolates.
The maximum number of packets they can make is
. To make the maximum number of packets, each packet should have
milk chocolates and
dark chocolates.

Answer 1

Milk chocolates = 28

Dark chocolates = 24

Total chocolates = 52

$\therefore$ if equally divided

no. of packets would be =>

$= \: \frac{52}{2} \\ = \: 26 \:packets$

Answer 2

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Given:

• No.of milk chocolates = 28
• No.of dark chocolates = 24

To Find:

1. Maximum number of packets each having same no of dark chocolates as well as of milk chocolates
2. No of dark and milk chocolates in each packet

Solution:

1) To find the maximum number of packets each having same no of dark chocolates as well as of milk chocolates we take HCF of 28 and 24.

HCF of 28 and 24 => 4

So, the maximum number of packets they can make is 4.

2) No. of dark chocolates in each packet = (Total dark chocolates)/(No. of packets) = (28)/(4) = 7

No. of milk chocolates in each packet = (Total milk chocolates)/(No. of packets) = (24)/(4) = 6

So, each packet should have 6 milk chocolates and 7 dark chocolates.

Hope It helps!!