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In this figure, m∠BDA = __° and m∠BCA = __°.
Answers
Answer:
Given
(ABC is an inscribed angle
Find out the mzBDA and mzBCA. To proof First
find the value of the central angle (
intercepted arc measure BA)
(BOA = 360° - 250°
= 110 °
Thus the intercepted arc AB is of
measure 110°
*FORMULA*
inscribed angle =
intercepted arc measure
thus putting the value in the above equation
we get
LBDA = ½(110°)
(BDA = 55°
Now find out (BCA
In the quadilateral AOBC
As shown in the diagram AC & BD are tangent
thus (CAO = 90°
(CBO = 90°
As we know the sum of a quadilateral is 360°
thus
(AOB + (CAO + (CBO + BCA = 360° Put the value as mentioned above
110° +90° + 90° +2BCA = 360°
(BCA = 360° - 290°
(BCA = 70°
Hence proved
Step-by-step explanation:
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Answer:
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Step-by-step explanation: