Type the correct answer in the box. Express the answer to three significant figures.
Given:
N2 + 3Cl2 → 2NCl3, ΔH = 464 kJ/mol
Use the given bond energies and the periodic table to calculate the energy change in the reaction.
The ΔH when 85.3 grams of chlorine reacts in the given reaction is kilojoules.
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Answer:
Δ∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine =
= 1.20 mol
Heat change when 1.20 mol chlorine reacts
=
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