Question

Type the correct answer in the box. In the above triangle, cosA/cosB = ?​

Answer 1

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$\displaystyle 1 = \frac{cos∠A}{cos∠B}$

$\displaystyle \frac{OPPOSITE}</p><p></p><ul><li>{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}</li></ul><p></p><p>{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}</p><p></p><p>{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}</p><p></p><p>{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}</p><p></p><p>{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}</p><p></p><p>{OPPOSITE} = cot\:θ$

Since this is a 45°-45°-90° triangle, you will have two IDENTICAL legs and the hypotenuse is the value of the leg multiplied by the square root of 2:

$\displaystyle x\sqrt{2} = HYPOTENUSE \\ x = LEGS \\ \\ 4,242640687 ≈ 3\sqrt{2} \\ \\ \frac{3}{4,242640687} ≈ cos∠B \\ \frac{3}{4,242640687} ≈ cos∠A \\ \\ \frac{\frac{3}{4,242640687}}{\frac{3}{4,242640687}} = 1$

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