Question

types of a triangle field are 15 metre 16 m and 17 M with the three corners of the field of a buffalo and a Horse I tried separately with the ropes of a lens and Mirrors 2 craze in the field find the area of the field which cannot be graced by the by three animals

Answer 1

Let ABC be the triangular field with sides Ac = 15 m, AB = 16 m and BC = 17 m
And,
Let the place where the cow, the buffalo and the horse are tied, are three sectors i.e. sector ADE, sector BFG and sector CHI 
The area of triangular field by Heron's formula =
√s(s-a)(s-b)(s-c)
s = (a+b+c)/2
s = (15+16+17)/2
s = 48/2
s = 24 m
√24(24-15)(24-16)(24-17)
√24*9*8*7
√12096
Area of triangular field = 109.98 sq m
Area of the grazed part = Area of the triangular field = Area of the sector ADE + Area of sector BFG + Area of sector CHI
= π*7²*∠A/360 + π*7²*∠B/360 + π*7²*∠C/360
= π*7²(∠ A + ∠ B + ∠ C)/360
= 22/7*7*7*180/360
= 154/2
Area of the grazed part = 77 sq m
Now, the area of the field which cannot be grazed by these animals 
= 109.98 - 77
= 32.98 sq m