Question

ПОИС, ЦУОU 0 (52+2y2) (7x2+3) 213x-2y) (5x+2y-у @ 6x 4s) tx+3)​

Answer 1

Answer:

$x3- 2x2y + 3xy2- y3+ 2x3- 5xy2 + 3x2y- 4y3. Collecting ... 5x3+ 3x3 + 3x3- x3- 5x2 + 2x2 - 2x2 - x2- x2 + 6x - 9x + 4x - 9x + x + 7 - 8 - 4 = 11x3 - x3 ... 4 - 5x + 6x2 - 8x3 - 6x3 + 7x2 - 5x + 3$

Answer 2

Step-by-step explanation:

x3−2x2y+3xy2−y3+2x3−5xy2 +3x2y−4y3.Collecting...5x3+3x3 +3x3−x3−5x2 +2x2 −2x2 −x2−x2 +6x−9x+4x−9x+x+7−8−4=11x3 −x3 ...4−5x+6x2 −8x3 −6x3 +7x2 −5x+3