u=0 ,v=40kmh,a=? pls answer jiska answer Sabse bada use Dunga brainliest
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Answer:
a is 5km/h by second equation of motion by third equation of motion you get distance
v2-u2=2as
40×40 =2×9.8×h
h=400/49
and by now second equation of motion
s=ut+1/2at2
s=0×t+1/2×9.8×t2
400/49= 1/2×9.8×t2
t2=1.6
a=v-u /t
a2=40-0/1.6
a2=400/16
a2= 25
a=5km/h
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