U=(1-2xy+y2)prove that d/DX((1-x2)du/dx)+d/du(y2du/du)=0
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f(x2 + y2, x2 - u2)=0. Solution: (a) ... uy/u = /. 1 - a2/y . Putting value of a from the first one into the second one gives the PDE.) (d) uxy - uyx = ... du/u2 x - y which gives dx x2. + dy y2. + du u2. = 0 ⇒ 1/x + 1/y + 1/u = c1 .
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