Question

(u+ 16)x x^2 + (u- 1)x +4 = 0​

Answer 1

Answer:

u=−16x3+x−4/x3+x

Step-by-step explanation:

you would solve for U and you would start by  Adding -16x^3 to both sides of the equation and you would get ux3+ux−x+4=−16x3 and then you would Add X to both sides as well and you would then have ux3+ux+4=−16x3+x so then you would Add -4 to both sides as well to get ux3+ux=−16x3+x−4 and then you would factor out the variable U and get u(x3+x)=−16x3+x−4 and then you would divide both sides by x^3+x. and you would end up with u=−16x3+x−4/x3+x

And please let me know if this helps.