Question

U-235,Ba-141,Kr-91 in this reaction 200Mev , how the energy released

Answer 1

here a heavy nucleus ( U-235 ) of low binding energy per neucleon is broken to lighter nucleus ( Ba-141 , Kr-91 ) of heigh binding energy per neucleon , in this process heavy nucleus will release energy and convert into lighter nucleus.
And this energy is about 200Mev