u=3m/s ,a =4m/s square,t=4s ,v=? use this formula v=u+at
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Given:-
Initial velocity(u)=3m/s
Acceleration(a)=4m/s²
Time(t)=4s
To find:-
Final velocity(v)
Solution:-
By using the first equation of motion,.i.e. v=u+at,we get---
=>v=3+4×4
=>v=3+16
=>v=19m/s
Thus,final velocity(v) is 19m/s.
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