Question

उंच इमारतीच्या गच्चीवरून खाली सोडलेल्या चेंडूचा 5 सेकंदानंतरचा वेग किती होईल?
98 मी./से.
122.5 मी./से.
24.5 मी./से.
49 मी./से.

Answer 1

Explanation:

Given उंच इमारतीच्या गच्चीवरून खाली सोडलेल्या चेंडूचा 5 सेकंदानंतरचा वेग किती होईल?

• Given what will be the speed of a ball dropped from the roof of a tall building after 5 secs.
• Now since the ball is dropped we have initial velocity u = 0 and a = g
• According to equation of motion we get
• S = ut + ½ gt^2
•    = 0 + ½ x 9.8 x 25
• Or S = 122.5 m
• Now we need to find the speed, so we get
• V^2 = u^2 + 2gs
• So v^2 = 0 + 2 x 9.8 x 122.5
• So v^2 = 2401
• Or v = 49 m/s
• Therefore speed of the ball is 49 m/s

Reference link will be

https://brainly.in/question/18715308