Question

(ü) Calculate the weight of 1.204 x 1023 molecules of CaCoz. (Use: NA = 6.02 x 1023)​

Answer 1

Answer:

=100g/mol

Explanation:

1 mole of CaCO

3

contains 6.022×10

23

molecules and 1 mole of CaCO

3

contains 1 mole of Ca, 1 mole of C and 3 moles of Oxygen.

Therefore, weight of 6.022×10

23

molecules of CaCO

3

= weight of 1 mole of CaCO

3

= (atomic mass of Ca) + (atomic mass of C) +3 (atomic mass of O) +

=40+12+(3×16)