U DU DUSU. U POVIL
A
The present age of a father exceeds that of his son by 20 years. Twenty years ago,
the
age of the father was five times that of his son. Find their present ages.
19.
Answers
Answered by
1
Step-by-step explanation:
Let F and S be the current ages of the father and son respectively.
From the first statement: F = 5 S
From the second statement:
F - 5 = 10(S - 5).
So F - 5 = 10S - 50 or F = 10S - 45
Combining this last equation with the first:
5S = 10S - 45
=>> 45 = 5S (adding 45 to both sides and subtracting 5S from both sides)
Dividing by 5 gives us 9 = S
So the father is 45 and the son is 9.
Five years ago they were 40 and 4.
Similar questions