U. (i) 8a³+ b³+ 12a²b + 6ab²
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Answered by
1
Answer:
8a³ + b³ + 12a²b + 6ab²
This can be re-written as: (2a)³ + (b)³ + 3(2a)²(b) + 3(2a)(b)²
which is of the form (x + y)³ = x³ + y³ + 3x²y + 3xy²
Here, x = 2a, y = b
Hence 8a³ + b³ +12a²b + 6ab² = (2a + b)³
Answered by
0
Step-by-step explanation:
8a3+b3= 8ab3+
12a2b+6ab2=8ab3+ 12a2b×6ab2
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