Question

U-
In a simple
pendulum velocity u=√7gl/2
is
given at lowest position
find out height at
which it will leave the circular path.​

Answer 1

Explanation:

ANSWER

Tension at highest point

T

H

=

r

mv

2

−mg=3mg−mg=2mg

and tension at lowest point

T

L

=

r

mv

2

+mg

Here, V

L

2

=3gr+2g.2r=7gr

So, T

L

=7mg+mg=8mg

Hence,

T

L

T

H

=

8mg

2mg

=

4

1