∆U is equal to
A)isochoric work
B)isobaric work
C)adiabatic work
D)isothermal work
please i want explanation also
Answers
Answered by
2
∆U is equal to D)isothermal work.
Explanation:
Isothermal process is the process in which temperature of the system remains constant. Therefore, internal energy remains constant.
For an ideal gas in an isothermal process, ∆U=0=Q-W.
where, ∆U= internal energy
Q = heat absorbed or released
W = work done by the system or on the system
Explanation:
Isothermal process is the process in which temperature of the system remains constant. Therefore, internal energy remains constant.
For an ideal gas in an isothermal process, ∆U=0=Q-W.
where, ∆U= internal energy
Q = heat absorbed or released
W = work done by the system or on the system
rahulmehta61:
its wrong
Answered by
6
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☬ YOUR ANSWER ☬
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This question can be solved by;
According to first law of thermodynamics ,
∆U = q + W = q - p∆V
in isochoric process (∆v = 0)
∆U = q
in isobaric process (∆p =0)
∆U = q
in adiabatic process ( q = 0)
∆U = W
in isothermal process (∆T = 0 )
and ∆U = 0
•°• ∆U is equal to adiabatic work.
so, answer is option C)
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
This question can be solved by;
According to first law of thermodynamics ,
∆U = q + W = q - p∆V
in isochoric process (∆v = 0)
∆U = q
in isobaric process (∆p =0)
∆U = q
in adiabatic process ( q = 0)
∆U = W
in isothermal process (∆T = 0 )
and ∆U = 0
•°• ∆U is equal to adiabatic work.
so, answer is option C)
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
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