Question

u(m/s)=0.... a(m/s2)=5... t(s)=5.. v=u+at (m/s)-------​

Answer 1

SOLUTION

TO DETERMINE

Complete the table below :

$\begin{gathered} \begin{array}{|c|c| c|c| } \bf{u \: (m/s)} & \bf{a \: (m/ {s}^{2} )}& \bf{t \: (sec)}& \bf{v = u + at \: \: (m/s)} \\ \\ 0 & 5 & 5 & - - \\ \\ - - & 1 & 8 &16 \\ \end{array}\end{gathered}$

EVALUATION

Here the given formula is v = u + at

ANSWER TO QUESTION : 1

Here it is given that

u = 0 , a = 5 , t = 5 , v = ?

Thus we get

$\sf{v = u + at }$

$\sf{ \implies \: v = 0 + (5 \times 5) }$

$\sf{ \implies \: v = 25 }$

So we have v = 25 m/s

ANSWER TO QUESTION : 2

Here it is given that

a = 1 , t = 8 , v = 16 , u = ?

Thus we get

$\sf{ v = u + at }$

$\sf{ \implies \: 16 = u + (1 \times 8) }$

$\sf{ \implies \: u + 8 = 16 }$

$\sf{ \implies \: u = 8}$

So we have u = 8 m/s

Hence the complete table is

$\begin{gathered} \begin{array}{|c|c| c|c| } \bf{u \: (m/s)} & \bf{a \: (m/ {s}^{2} )}& \bf{t \: (sec)}& \bf{v = u + at \: \: (m/s)} \\ \\ 0 & 5 & 5 & 25\\ \\ 8 & 1 & 8 &16 \\ \end{array}\end{gathered}$

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