Question

U-tube manometer is used to measure the pressure of water in a pipe line, which is in excess of atmospheric pressure. The right limb of the manometer contains mercury and is open to atmosphere. The contact between water and mercury is in the left limb. Determine the pressure of water in the main line, if the difference in level of mercury in the limbs of U-tube is 10 cm and the free surface of mercury is in level with the centre of the pipe. If the pressure of water in pipe line is reduced to 9810 N/m2, calculate the new difference in the level of mercury. Sketch the arrangements in both cases.
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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The new difference in the level of mercury. Sketch the arrangements in both cases is  114.66kPa.

Explanation:

Step 1: A manometer is a device used to measure flow or pressure that contains a tiny, U-shaped tube filled with liquid. The mitigation system's fan is monitored using a U-tube manometer to determine whether it is operating properly.

Step 2: The manometer makes use of the hydrostatic (standing liquid) balance principle, which gauges pressure in terms of how much liquid it can sustain in height. For instance, a column of mercury with a cross sectional area of one inch, one inch high, and 0 degrees Celsius weighs 4892 pounds.

Step 3:$P_{\mathrm{atm}}=101.325 \mathrm{kPa}$

$P_w$ - pressure exerted by water

$P_N=P_{\mathrm{tm}}++9 h$

$P_N=\left(101.325 \times 10^3\right)+\left(13.6 \times 10^3 \times 9.91 \times 10 \times 10^{-2}\right)$

$R=114.66 \mathrm{kPa}$

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