Question

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$(a^{3} - \dfrac{3}{8})(a^{3} + \dfrac{16}{17})$

ANSWER PLSS

Answer 1

\begin{align*} \frac{{x}^{2} + 3x}{x + 3} & = \frac{x\left(x + 3\right)}{x + 3}\\ & =x \qquad \qquad \left(x\ne ... If \(x =-3\) then the denominator, \(x + 3 = 0\) and the fraction is undefined. ... \(\dfrac{a^2 + 6a - 16}{a^3 - 8}\).