U will be marked as Brainliest if u solve those questions above so plz help!
Answers
Answer:
sorry i am from 8th class this is tough for me
Step-by-step explanation:
1). Determine S1, S2 and S3 in terms of x
area of S1
= area of rectangle = length × breadth
= (3x-1) × (x+1)
= 3x² + 3x - 1x - 1
= 3x² + 2x - 1
area of S2
= area of square = (side)²
= (3x - 1)²
= 9x² - 6x + 1
area of S3
= area of triangle = 1/2 × length × breadth
= 1/2 × (3x-1) × (x+1)
= 1/2 ×( 3x² + 2x - 1)
= 3x²/2 + x - 1/2
2). solve S1 - 2S2 + 2S3 = 0
= 3x² + 2x - 1 - 2(9x² - 6x + 1) + 2(3x²/2 + x - 1/2) = 0
= 3x² + 2x - 1 - 18x² + 12x - 2 + 3x² + 2x - 1 = 0
= (3x² - 18x² + 3x²) + (2x + 12x + 2x) + (-1 -2 -1) = 0
= -12x² + 16x - 4 = 0
= 12x² - 16x + 4 = 0
= 12x² -12x -4x + 4 = 0
= 12x(x - 1) -4(x - 1) = 0
= (12x - 4)(x - 1) = 0
12x - 4 = 0
12x = 4
x = 4/12
x = 1/3
and
x - 1 = 0
x = 1