Math, asked by Jzjndnx, 2 months ago

U will be marked as Brainliest if u solve those questions above so plz help! ​

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Answered by pranjalawasthi21
1

Answer:

sorry i am from 8th class this is tough for me

Answered by karmaan958
1

Step-by-step explanation:

1). Determine S1, S2 and S3 in terms of x

area of S1

= area of rectangle = length × breadth

= (3x-1) × (x+1)

= 3x² + 3x - 1x - 1

= 3x² + 2x - 1

area of S2

= area of square = (side)²

= (3x - 1)²

= 9x² - 6x + 1

area of S3

= area of triangle = 1/2 × length × breadth

= 1/2 × (3x-1) × (x+1)

= 1/2 ×( 3x² + 2x - 1)

= 3x²/2 + x - 1/2

2). solve S1 - 2S2 + 2S3 = 0

= 3x² + 2x - 1 - 2(9x² - 6x + 1) + 2(3x²/2 + x - 1/2) = 0

= 3x² + 2x - 1 - 18x² + 12x - 2 + 3x² + 2x - 1 = 0

= (3x² - 18x² + 3x²) + (2x + 12x + 2x) + (-1 -2 -1) = 0

= -12x² + 16x - 4 = 0

= 12x² - 16x + 4 = 0

= 12x² -12x -4x + 4 = 0

= 12x(x - 1) -4(x - 1) = 0

= (12x - 4)(x - 1) = 0

12x - 4 = 0

12x = 4

x = 4/12

x = 1/3

and

x - 1 = 0

x = 1

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