U will get 25 mark nd i will mark u brainliest.....plz it's urgent....
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Answers
Answered by
1
The correct option is (C)
You may check it by putting values of.
X= 24
y= 9
z= 5
---------------------------------
Now, How i get it⤵⤵⤵
I have taken 1st given equation.
1/3(x+y)+ 2z= 21
Now, if you see all options [other than (c)]
You observe that (x+y) is not complete devisible by 3
Hence, we can't get LHS=RHS.
Only C option is satisfying the equation
====================
Hope you get it :)
#AMRIT⭐
You may check it by putting values of.
X= 24
y= 9
z= 5
---------------------------------
Now, How i get it⤵⤵⤵
I have taken 1st given equation.
1/3(x+y)+ 2z= 21
Now, if you see all options [other than (c)]
You observe that (x+y) is not complete devisible by 3
Hence, we can't get LHS=RHS.
Only C option is satisfying the equation
====================
Hope you get it :)
#AMRIT⭐
Answered by
0
Answer:
The correct option is (C)
You may check it by putting values of.
X= 24
y= 9
z= 5
---------------------------------
Now, How i get it⤵⤵⤵
I have taken 1st given equation.
1/3(x+y)+ 2z= 21
Now, if you see all options [other than (c)]
You observe that (x+y) is not complete devisible by 3
Hence, we can't get LHS=RHS.
Only C option is satisfying the equation
====================
Hope you get it :)
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